what should be the value of x if
![1000 \div 2 {}^{2} \times 3 {}^{x} \times 5 {}^{2} 1000 \div 2 {}^{2} \times 3 {}^{x} \times 5 {}^{2}](https://tex.z-dn.net/?f=1000+%5Cdiv+2+%7B%7D%5E%7B2%7D++%5Ctimes+3+%7B%7D%5E%7Bx%7D++%5Ctimes+5+%7B%7D%5E%7B2%7D+)
is a terminating decimal
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Answer.
Since, for any rational number p/q, q is of the form 2ᵐ × 5ⁿ , so the value of x must be 0.
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hey
The value of x should be 0
because
there should not be 3 in denominator
a^0 = 1
thus 3^0 = 1
and then it becomes a terminating decimal
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