What should be the width of each slit to obtain n maxima of double slit
pattern within the central maxima of single slit pattern?
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Answer:
given = n maxima ; a = width of the slit
to find = width of each slit
solution =
β₀ = 2Dλ / a
β₀ = 10β
2Dλ/a = 10 X 5 X 10⁻⁴
a = 2 X 1 X 500 X 10⁻⁹/ 10 X 5 X 10⁻⁴
a = 0.2mm
OR
∴ nλ / d = 2λ/ a
∴n =2d/a
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