Question

what should betime takenby earth to move one round its own axis so that body on its equator flies off​

Answer 1

Answer:

Explanation:

for a person to fly off, the earth should be spinning at a speed where the centrifugal force due to rotation is equal to the gravitational pull of the earth at the surface.

So,

therefore,

9.81 = (V^2)/r

v = sqrt (9.81*6400(1000))

v = 7,923.63 m/sec.

Thus, the velocity at the surface of earth will be 7923 m/sec

Circumference of the earth is 40,075 km = 40075000 m

time required to complete of revolution = 40075000/7923.63

= 5075 sec

= 1.404 hours = 1 hour 24 minutes

For a person to fly off, the earth should be moving at nearly 8000 m/sec.

This would mean that the day on earth would last for about 1 hour and 24 minutes.