Math, asked by nithwik9032, 11 months ago

What should subtract from 4^15 qhen remainder gets divisible by 31?

Answers

Answered by 6bits
0

Answer:

1

Step-by-step explanation:

4^15/31=64^5/31=2^5/31=32/31

1 must be subtracted from given expression for divisibility of 31

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