Question

What should the co efficient of friction between tyres and road when car is travelled at 60km/h makes a level of turn of radius 40cm

Answer 1

Answer:

in the question the radius of turn is given 40 cm, but if the radius is taken as it is then the value of coefficient of friction is 70.7, which is not possible, hence i assumed the radius as 40 m.

Explanation:

v = 60 km/h = 16.66 m/s

r = 40 m, g = 9.81 m/s^2

coefficient of friction = v^2/(r*g)

= (16.66^2)/(40*9.81) = 0.707