Question

what should we add into x³ - 76 so it should be exactly divisible by x-4?​

Answer 1

Answer:

x³ - 76÷x - 4 we get

( x²-4x+16) is quotient

-12 =remainder

Please mark me Brilliant answer..

Answer 2

Explanation:

We know that x³ - a³ = ( x - a )( x² + ax + a² )

Let x³ - 76 = x³ - 64 - 12

= x³ - 4³ - 12

= ( x - 4 )( x² + 4x + 4²) - 12

x³ - 76 + 12 = ( x - 4 )( x² + 4x + 16

x³ - 64/( x - 4)= ( x² + 4x + 16 )

Therefore we should add 12 to x³ - 76 to be exactly divisible by x - 4