Question

what should we added to -mn²+2mn-n²to get 4mn+m²+n²m​

Answer 1

Answer:

2mn + m² + n²m + mn² + n²

Step-by-step explanation:

let the no be = x

4mn + m² + n²m + x = -mn² + 2mn - n²

∴ x = 4mn + m² + n²m - ( -mn² +2mn - n²)

4mn + m² + n²m + mn² - 2mn + n²       (remove the brackets)

2mn + m² + n²m + mn² + n²      ( 4mn and -2mn are like terms)

∴ 2mn + m² + n²m + mn² + n² should be added to -mn²+ 2mn -n² to get 4mn +m²+ n²m​