what shuld be added to 3l³+2l²+lm to get l²-3lm.
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Answer:
-4lm-4l²
Step-by-step explanation:
Let the number be x
3l³+2l²+lm+(x)=l²-3lm
x=l²-3lm-(3l²+2l²+lm)
x=l²-3lm-3l²-2l²-lm
x=(-4lm-4l²)
-4lm-4l² should be added to 3l²+2l²+lm to get l²-3lm
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