Math, asked by bhumibhatt950, 10 hours ago

what smallest no. must be multiplied in the denominator so that the decimal no. 14588 / 625 will be terminated? ​

Answers

Answered by msoumen419
19

Answer:

If the factors of denominator of the given rational number is of the form 2ⁿ 5^m , where n and m are nonnegative integers, then the decimal expansion of the decimal number is terminating otherwise non terminating recurring.

14588/625

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Step-by-step explanation:

14588/625

The factors of the denominator 625 is 5⁴ × 2^0. So it has a terminating decimal expansion.

Now, 14588/625 = 14588 ×2⁴ / 5⁴ × 2⁴

14588/625 =14588 × 16 / (10)⁴

= 233408/10⁴

= 233408/10000

= 23.3408

It will terminate after 4 places of decimal.

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Answered by rpinfinityuniverse
5

Answer:

4 is the answer ...

hope it will help u

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