what steps are used in drafting ??? (no need in order)
Answers
Explanation:
Given :
Length = 1 m
Resistivity \tt \rho = 1.84 \times 10^{-6}ρ=1.84×10
−6
Ωm .
Diameter (D) = 3 × \tt 10^{-4}10
−4
Temperature (T) = 20 °C
To find :
The resistance of the manganese wire
Solution :
The radius of the area of cross section is D/2
\tt = \dfrac{3}{2} \times 10^{ - 4}=
2
3
×10
−4
Area of the cross section of wire = πr²
= \tt \dfrac{22}{7} \times \dfrac{3}{2} \times \dfrac{3}{2} \times {10 }^{ - 4} \times {10}^{ - 4}=
7
22
×
2
3
×
2
3
×10
−4
×10
−4
$$\begin{lgathered}= \tt \dfrac{198}{28} \times {10}^{ - 8} \\ \\ \tt = 7.07 \times {10}^{ - 8} {m}^{2}\end{lgathered}$$
The resistance of the wire is given by the formula :
$$\boxed{ \tt R = \rho \: \: \dfrac{l}{A} }$$
$$\tt = 1.84 \times {10}^{ - 6} \times \dfrac{1}{7.07 \times {10}^{ - 8} }$$
$$\tt = \dfrac{1.84 \times {10}^{ - 6} \times {10}^{8} }{7.07}$$
$$\tt = \dfrac{184 \times {10}^{2} }{707}$$
$$\tt = 26.025 \: \Omega$$
Hence the resistance of Manganese wire is 26.025 Ω .
_____________________________
$$\underline{ \underline{ \large{ \mathfrak \orange{Resistance : }}}}$$
The property of a matter to oppose the flow of electric current in it is called resistance .
It is defined as the ratio of potential difference to the current flowing in the circuit .
Resistance vary
directly with length .
indirectly with area of cross section.
Nature of the material.
Explanation:
Writing first draft
RE drafting
Writing the final draft
I HOPE THIS MAY HELP YOU