Question

what sum invested for 3/2 years compound interest payable half yearly, find rate of interest per annum​

Answer 1

p (1+R)/100

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Answer 2

HEY MATE HERE IS YOUR ANSWER..

Step-by-step explanation:

Solution :

Solution :Here, P = $1,000, R = 10% and n = 18

months = 18/12 = 3/2 years.

months = 18/12 = 3/2 years.Amount after 2 years = P ( 1 + r/2)2n

months = 18/12 = 3/2 years.Amount after 2 years = P ( 1 + r/2)2n= 1,000 ( 1 + 0.10 /2)2 x 3/2

months = 18/12 = 3/2 years.Amount after 2 years = P ( 1 + r/2)2n= 1,000 ( 1 + 0.10 /2)2 x 3/2= 1,000 ( 1 + 0.05)6/2

months = 18/12 = 3/2 years.Amount after 2 years = P ( 1 + r/2)2n= 1,000 ( 1 + 0.10 /2)2 x 3/2= 1,000 ( 1 + 0.05)6/2= 1,000 (1.05)3

months = 18/12 = 3/2 years.Amount after 2 years = P ( 1 + r/2)2n= 1,000 ( 1 + 0.10 /2)2 x 3/2= 1,000 ( 1 + 0.05)6/2= 1,000 (1.05)3= 1,000 x 1.157625

months = 18/12 = 3/2 years.Amount after 2 years = P ( 1 + r/2)2n= 1,000 ( 1 + 0.10 /2)2 x 3/2= 1,000 ( 1 + 0.05)6/2= 1,000 (1.05)3= 1,000 x 1.157625Amount = $ 1157.625

months = 18/12 = 3/2 years.Amount after 2 years = P ( 1 + r/2)2n= 1,000 ( 1 + 0.10 /2)2 x 3/2= 1,000 ( 1 + 0.05)6/2= 1,000 (1.05)3= 1,000 x 1.157625Amount = $ 1157.625∴ C.I = A - P

months = 18/12 = 3/2 years.Amount after 2 years = P ( 1 + r/2)2n= 1,000 ( 1 + 0.10 /2)2 x 3/2= 1,000 ( 1 + 0.05)6/2= 1,000 (1.05)3= 1,000 x 1.157625Amount = $ 1157.625∴ C.I = A - PC.I = 1157.625 - 1000

months = 18/12 = 3/2 years.Amount after 2 years = P ( 1 + r/2)2n= 1,000 ( 1 + 0.10 /2)2 x 3/2= 1,000 ( 1 + 0.05)6/2= 1,000 (1.05)3= 1,000 x 1.157625Amount = $ 1157.625∴ C.I = A - PC.I = 1157.625 - 1000C.I = $ 157.625

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