what sum of money amounts to rupees 15246 in 2 year's compounded annually at 10% per annum
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Answer:
Step-by-step explanation:
Let No. of Years = n
Given that
Principal amount (P) = 12600
Rate of Interest (R) = 10 %
Compound Interest (I)
= 15246 - 12600
= 2646
As per compound Interest formula
I = P ( 1+r/100)^n
2646 = 12600 (1+10/100)^n
2646/12600 = (110/100)^n
21/100 = (110/100)^n
as per trail & error method, put n=2
21/100 = (110/100)^2
21/100 = 110×110/100×100
21 = 100 for 2 years
100 ---- 110 ----- 121
we have to pay the interest for ₹100 for first year = ₹10 {100×10/100} = ₹10
we have to pay the interest for ₹110 for 2nd year = ₹21
{110×10/100} = ₹21
so no. of years = 2 years
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