Question

What sum of money borrowed on 1“ May will amount to 2 55,440 on 23rd September of the same year at 5%
p.a simple interest?
-Please try to help
-no free points​

Answer 1

Days between 1 may to 23 September

= 145 days

Time of year taken = 145/365=29/73

Rate=5% p.a.

Let the Principal be p

SI = Amount-P = 2,55,440-P

SI = PRT/100

$255440 - p = \frac{p \times 5 \times 29}{100 \times 73} \\ = > 255440 - p = \frac{145p}{7300} \\ = > 255440 - p(7300) = 145p \\ 1864712000 - 7300p = 145p \\ = > 1864712000 = 145p + 7300p \\ = > 1864712000 = 7445p \\ = > \frac{1864712000}{7445} = p \\ = > about250465 = p$

Hope it helps you

Please mark me brainliest

Jai Shree Ram

108 ॐ