What sum of money borrowed on 24 may will amount to 10210.20 on 17 october of the ame year at 5% per annum simple interest
Answers
Answered by
65
Here, time
May June July August September October
= 7 + 30 + 31 + 31 + 30 + 17
=146 days
=146/365 years.
R=5% per annum and let principal=P
∴, S=(P×T×R)/100
or, 10210.20=[P×(146/365)×5]/100
or, 10210.20×100=(P×146×5)/365
or, 1021020=(P×146)/73
or, 1021020=P×2
or, P=1021020/2
or, P=510510 Ans.
May June July August September October
= 7 + 30 + 31 + 31 + 30 + 17
=146 days
=146/365 years.
R=5% per annum and let principal=P
∴, S=(P×T×R)/100
or, 10210.20=[P×(146/365)×5]/100
or, 10210.20×100=(P×146×5)/365
or, 1021020=(P×146)/73
or, 1021020=P×2
or, P=1021020/2
or, P=510510 Ans.
Answered by
2
Answer:
Rs.10175.4
Step-by-step explanation:
Amount = Rs.10210.20
Let Principal be x
Simple interest = Amount - Principal = 10210.20-x
Time = 24 may - 17 October = 25 days
Rate of interest = 5%
SI =
Hence The principal is Rs.10175.4
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