Question

What sum of money lent out at simple interest at
10% per annum for 1 sided 2 upon 3 years will produce the same
interest as Rs. 500 lent at 5% per annum for 6 years ?

​

Answer 1

Answer:

• Sum of money is Rs 2250.

Step-by-step explanation:

Given that:

Case I,

• Rate of Interest = 10% per annum
• Time period = 2/3 years
• Let the principal be P.

Case II,

• Principal = Rs 500
• Rate of Interest = 5% per annum
• Time period = 6 years

It's also given: Simple Interest for both cases are same.

To Find:

• Principal/The sum of money for the case I.

Formula used:

• S.I. = (P × R × T)/100

Where,

• S.I. = Simple Interest
• P = Principal/Sum of money
• R = Rate of Interest
• T = Time period

Finding the sum of money for Case I:

According to the question.

⟶ (P × 10 × 2/3)/100 = (500 × 5 × 6)/100

Cancelling 100 both sides.

⟶ 20P/3 = 15000

⟶ 20P = (15000 × 3)

⟶ P = (15000 × 3)/20

⟶ P = 2250

∴ The sum of money = Rs 2250

Answer 2

$\huge\mathfrak\red{hello}$

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

$sum \: of \: money = rs \: 2250$

$\huge\mathfrak\blue{what we \: have \: to \: find:-}$

$\frac{principal}{sum \: of \: money} \: \: \: for \: case \: 1$

$\huge\sf\green{formula - }$

$s.i. = \frac{p \times r \times t}{100}$

➖➖➖➖➖➖➖➖➖➖

$\huge\sf\red{case \: 1}$

• Rate Of Interest = 10% per annum
• Time Period = 2/3 years
• Let Principal be = P

CASE 2

• principal = Rs 500
• rate of interest = 5 percent per annum
• time period = 6 years

$‣ \: \: \: \frac{p \times 10 \times \frac{2}{3} }{100} = \frac{500 \times 5 \times 6}{100} \\ \\ ‣ \frac{20p}{3} = 15000 \\ \\ ‣ \: p = 2250$

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