Question

What sum of money put of simple interest for 2 years at 8% will amount to 1276 ?

Answer 1

$\sf{\underline{\boxed{\large{\blue{\mathsf{Solution}}}}}}$

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• Amount = Rs. 1276
• Rate = 8%
• Time = 2 years

_______________________

$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• Principle = ??

______________________

$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

$\sf{\red{\boxed{\bold{Amount = Principle + Interest}}}}$------ ( i )

⠀⠀⠀⠀

$\sf{\red{\boxed{\bold{Interest = \dfrac{p\times r\times t}{100}}}}}$---- ( ii )

⠀⠀

• From eq. ( i ) and ( ii )

⠀⠀⠀⠀

$\sf{\red{\boxed{\bold{Amount = P + \dfrac{prt}{100}}}}}$

⠀⠀⠀⠀

• Let principle be p

$\sf: \implies \:{\bold{ 1276 = p + \dfrac{ p \times 8 \times 2}{100}}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ 1276 = p + \dfrac{ p \times 8 }{50}}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ 1276 = p + \dfrac{ p \times 4}{25}}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ 1276 = \dfrac{25p + 4p}{25}}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ 1276 = \dfrac{29p}{25}}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ p = {1276\times 25}{29}}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ p = 44 \times 25}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ p = Rs. 1100 }}$

______________________

$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

• Rs. 1100 will amount to Rs.1276 in 2 years at 8% ler annum

Answer 2

Step-by-step explanation:

SI=PRT/100

SI=1276(Given)

p×8×2/100=1276

16p/100=1276

16p=127600

p=7975

note

here, SI stand for simple interest

p for principal

r for rate

t for time