what sum of money will amount 3630 in 2 years at 10% per annum compounded anually
Answers
Answer:
Here is your answer see the picture
Step-by-step explanation:
Given:-
Amount = Rs. 3630
Rate of interest = (R) =10%p.a
Time (n) = 2 years
\begin{gathered}Amount = P ({1 + \frac{R}{100} )}^{n} \\ = P ({1 + \frac{R}{100} )}^{2} = 3630 \\ \\ = P ({1 + \frac{10}{100} )}^{2} = 3630 \\ \\ = P ({1 + \frac{1}{10} )}^{2} = 3630 \\ \\ = P {( \frac{10 + 1}{10} )}^{2} = 3630 \\ \\ = P {( \frac{11}{10} )}^{2} = 3630 \\ \\ = P \times \frac{121}{100} = 3630 \\ \\ = P = 3630 \div \frac{121}{100} \\ \\ = P = 3630 \times \frac{100}{121} \\ \\ = P = 30 \times 100 \\ \\ = P = 3000\end{gathered}
Amount=P(1+
100
R
)
n
=P(1+
100
R
)
2
=3630
=P(1+
100
10
)
2
=3630
=P(1+
10
1
)
2
=3630
=P(
10
10+1
)
2
=3630
=P(
10
11
)
2
=3630
=P×
100
121
=3630
=P=3630÷
100
121
=P=3630×
121
100
=P=30×100
=P=3000
So Principal = Rs. 3000
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