What sum of money will
amount to 5310 in 3 years at 6% per annum
Answers
Answered by
0
Let the principal be x
Rate of dividend = 6%
Time = 3 years = 12*3=36 months
Money received = 5310
Therefore, money deposited = 36x
SI= 5310-36x
So applying the formula,
SI = P* n(n*1)/2* 1/12 * R/100
On substituting , we get:
5310-36x= x*36*37/2*1/12*6/100
2400(5310-36x)= 7992x
1,27,44,000-86400x=7992x
12744000= 94392x
135.01=x
Rate of dividend = 6%
Time = 3 years = 12*3=36 months
Money received = 5310
Therefore, money deposited = 36x
SI= 5310-36x
So applying the formula,
SI = P* n(n*1)/2* 1/12 * R/100
On substituting , we get:
5310-36x= x*36*37/2*1/12*6/100
2400(5310-36x)= 7992x
1,27,44,000-86400x=7992x
12744000= 94392x
135.01=x
Similar questions