Question

what sum of money will amount to Rs.3630 in 2 yrs at 10%pa compound interest?

Plz help its urgent...

Answer 1

Given:-
Amount = Rs. 3630
Rate of interest = (R) =10%p.a
Time (n) = 2 years

$Amount = P ({1 + \frac{R}{100} )}^{n} \\ = P ({1 + \frac{R}{100} )}^{2} = 3630 \\ \\ = P ({1 + \frac{10}{100} )}^{2} = 3630 \\ \\ = P ({1 + \frac{1}{10} )}^{2} = 3630 \\ \\ = P {( \frac{10 + 1}{10} )}^{2} = 3630 \\ \\ = P {( \frac{11}{10} )}^{2} = 3630 \\ \\ = P \times \frac{121}{100} = 3630 \\ \\ = P = 3630 \div \frac{121}{100} \\ \\ = P = 3630 \times \frac{100}{121} \\ \\ = P = 30 \times 100 \\ \\ = P = 3000$
So Principal = Rs. 3000

Answer 2

A=3630

T=2yrs

R=10%

A=p(1+r/100)^t

3630=p(1+10/100)^2

3630=p(11/10)^2

3630=121p/100

P=3630*100/121

P=3000