Math, asked by ajha55831, 1 month ago

what sum of money will earn rs 2550 intrest in 3 years, if the rate of interest is 5%/annum​

Answers

Answered by Anonymous
41

\large\sf\underline{Question\::}

  • What sum of money will earn Rs 2550 interest in 3 years if the rate of interest is 5 % per annum ?

\large\sf\underline{Answer\::}

  • The principal oR the sum of money on which interest for 3 years at 5 % per annum becomes Rs 2550 is \tt\blue{Rs\:17000}

____________________________‎

\large\sf\underline{Given\::}

  • Simple interest ( SI ) = Rs 2550

  • Time ( T ) = 3 years

  • Rate of interest ( R ) = 5 % per annum

\large\sf\underline{To\:find\::}

  • Sum of money oR Principal ( P ) on which interest for 3 years becomes Rs 2550 .

\large\sf\underline{Formula\:to\:be\:used\::}

\bf\dag \large{\mathfrak\purple{P\:=\:\frac{SI \times 100}{R \times T}}}

where :

  • P = Principal

  • SI = Simple Interest

  • R = Rate

  • T = Time

\large\sf\underline{Solution\::}

\sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}

  • Substituting the given values in the formula

\sf\dashrightarrow\:Principal\:=\frac{2550 \times 100}{5 \times 3}

  • Proceeding with multiplication

\sf\dashrightarrow\:Principal\:=\frac{255000}{15}

  • Reducing it to lower terms

\sf\dashrightarrow\:Principal\:=\cancel{\frac{255000}{15}}

\sf\dashrightarrow\:Principal\:=\cancel{\frac{51000}{3}}

\sf\dashrightarrow\:Principal\:=\cancel{\frac{17000}{1}}

\small{\underline{\boxed{\mathrm\red{\dashrightarrow\:Principal\:=\:Rs\:17000}}}}

Hence ,

  • The required principal would be Rs 17000 .

____________________________

\large\sf\underline{Verifying\::}

Not sure about the answer !?

Let's verify it for our self satisfaction .

We would verify by substituting the given values and the value which we got as Principal in the formula. If we get LHS and RHS as equal , our answers must be correct.

\sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}

\sf\leadsto\:17000\:=\frac{2550 \times 100}{5 \times 3}

\sf\leadsto\:17000\:=\frac{255000}{15}

\sf\leadsto\:17000\:=\cancel{\frac{255000}{15}}

\sf\leadsto\:17000\:=17000

{\sf{{\green{Hence\:verified}}}}

____________________________‎

!! Hope it helps !!

Answered by Anonymous
7

\large\sf\underline{Question\::}

Question:

What sum of money will earn Rs 2550 interest in 3 years if the rate of interest is 5 % per annum ?

\large\sf\underline{Answer\::}

Answer:

The principal oR the sum of money on which interest for 3 years at 5 % per annum becomes Rs 2550 is \tt\blue{Rs\:17000}Rs17000

____________________________‎

\large\sf\underline{Given\::}

Given:

Simple interest ( SI ) = Rs 2550

Time ( T ) = 3 years

Rate of interest ( R ) = 5 % per annum

\large\sf\underline{To\:find\::}

Tofind:

Sum of money oR Principal ( P ) on which interest for 3 years becomes Rs 2550 .

\large\sf\underline{Formula\:to\:be\:used\::}

Formulatobeused:

\bf\dag† \large{\mathfrak\purple{P\:=\:\frac{SI \times 100}{R \times T}}}P=

R×T

SI×100

where :

P = Principal

SI = Simple Interest

R = Rate

T = Time

\large\sf\underline{Solution\::}

Solution:

\sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}Principal=

Rate×Time

SimpleInterest×100

Substituting the given values in the formula

\sf\dashrightarrow\:Principal\:=\frac{2550 \times 100}{5 \times 3}⇢Principal=

5×3

2550×100

Proceeding with multiplication

\sf\dashrightarrow\:Principal\:=\frac{255000}{15}⇢Principal=

15

255000

Reducing it to lower terms

\sf\dashrightarrow\:Principal\:=\cancel{\frac{255000}{15}}⇢Principal=

15

255000

\sf\dashrightarrow\:Principal\:=\cancel{\frac{51000}{3}}⇢Principal=

3

51000

\sf\dashrightarrow\:Principal\:=\cancel{\frac{17000}{1}}⇢Principal=

1

17000

\small{\underline{\boxed{\mathrm\red{\dashrightarrow\:Principal\:=\:Rs\:17000}}}}

⇢Principal=Rs17000

Hence ,

The required principal would be Rs 17000 .

____________________________

\large\sf\underline{Verifying\::}

Verifying:

Not sure about the answer !?

Let's verify it for our self satisfaction .

We would verify by substituting the given values and the value which we got as Principal in the formula. If we get LHS and RHS as equal , our answers must be correct.

\sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}Principal=

Rate×Time

SimpleInterest×100

\sf\leadsto\:17000\:=\frac{2550 \times 100}{5 \times 3}⇝17000=

5×3

2550×100

\sf\leadsto\:17000\:=\frac{255000}{15}⇝17000=

15

255000

\sf\leadsto\:17000\:=\cancel{\frac{255000}{15}}⇝17000=

15

255000

\sf\leadsto\:17000\:=17000⇝17000=17000

‎{\sf{{\green{Hence\:verified}}}}Henceverified

____________________________‎

!! Hope it helps !!

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