what sum of money will earn rs 2550 intrest in 3 years, if the rate of interest is 5%/annum
Answers
- What sum of money will earn Rs 2550 interest in 3 years if the rate of interest is 5 % per annum ?
- The principal oR the sum of money on which interest for 3 years at 5 % per annum becomes Rs 2550 is
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- Simple interest ( SI ) = Rs 2550
- Time ( T ) = 3 years
- Rate of interest ( R ) = 5 % per annum
- Sum of money oR Principal ( P ) on which interest for 3 years becomes Rs 2550 .
where :
- P = Principal
- SI = Simple Interest
- R = Rate
- T = Time
- Substituting the given values in the formula
- Proceeding with multiplication
- Reducing it to lower terms
★
Hence ,
- The required principal would be Rs 17000 .
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Not sure about the answer !?
Let's verify it for our self satisfaction .
We would verify by substituting the given values and the value which we got as Principal in the formula. If we get LHS and RHS as equal , our answers must be correct.
____________________________
!! Hope it helps !!
\large\sf\underline{Question\::}
Question:
What sum of money will earn Rs 2550 interest in 3 years if the rate of interest is 5 % per annum ?
\large\sf\underline{Answer\::}
Answer:
The principal oR the sum of money on which interest for 3 years at 5 % per annum becomes Rs 2550 is \tt\blue{Rs\:17000}Rs17000
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\large\sf\underline{Given\::}
Given:
Simple interest ( SI ) = Rs 2550
Time ( T ) = 3 years
Rate of interest ( R ) = 5 % per annum
\large\sf\underline{To\:find\::}
Tofind:
Sum of money oR Principal ( P ) on which interest for 3 years becomes Rs 2550 .
\large\sf\underline{Formula\:to\:be\:used\::}
Formulatobeused:
\bf\dag† \large{\mathfrak\purple{P\:=\:\frac{SI \times 100}{R \times T}}}P=
R×T
SI×100
where :
P = Principal
SI = Simple Interest
R = Rate
T = Time
\large\sf\underline{Solution\::}
Solution:
\sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}Principal=
Rate×Time
SimpleInterest×100
Substituting the given values in the formula
\sf\dashrightarrow\:Principal\:=\frac{2550 \times 100}{5 \times 3}⇢Principal=
5×3
2550×100
Proceeding with multiplication
\sf\dashrightarrow\:Principal\:=\frac{255000}{15}⇢Principal=
15
255000
Reducing it to lower terms
\sf\dashrightarrow\:Principal\:=\cancel{\frac{255000}{15}}⇢Principal=
15
255000
\sf\dashrightarrow\:Principal\:=\cancel{\frac{51000}{3}}⇢Principal=
3
51000
\sf\dashrightarrow\:Principal\:=\cancel{\frac{17000}{1}}⇢Principal=
1
17000
\small{\underline{\boxed{\mathrm\red{\dashrightarrow\:Principal\:=\:Rs\:17000}}}}
⇢Principal=Rs17000
★
Hence ,
The required principal would be Rs 17000 .
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\large\sf\underline{Verifying\::}
Verifying:
Not sure about the answer !?
Let's verify it for our self satisfaction .
We would verify by substituting the given values and the value which we got as Principal in the formula. If we get LHS and RHS as equal , our answers must be correct.
\sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}Principal=
Rate×Time
SimpleInterest×100
\sf\leadsto\:17000\:=\frac{2550 \times 100}{5 \times 3}⇝17000=
5×3
2550×100
\sf\leadsto\:17000\:=\frac{255000}{15}⇝17000=
15
255000
\sf\leadsto\:17000\:=\cancel{\frac{255000}{15}}⇝17000=
15
255000
\sf\leadsto\:17000\:=17000⇝17000=17000
{\sf{{\green{Hence\:verified}}}}Henceverified
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!! Hope it helps !!