Question

what sum of money will to rs. 3630 in 2 years at 10% per annum compound interest (using formula)​

Answer 1

To Find :

The sum of money .

Given :

• Principal = ₹ 3630

• Rate of interest = 10% p.a.

• Time = 2 years

We Know :

Amount Formula :

$\purple{\sf{\underline{\boxed{A = P\bigg(1 + \dfrac{R}{100}\bigg)^{n}}}}}$

Where ,

• A = Amount

• P = Principal

• R = Rate of interest

• n = Time period

Solution :

Using the formula and substituting the values in it , we get :

$\purple{\sf{A = P\bigg(1 + \dfrac{R}{100}\bigg)^{n}}} \\ \\ \\ \implies \sf{A = 3630\bigg(1 + \dfrac{10}{100}\bigg)^{2}} \\ \\ \\ \implies \sf{A = 3630\bigg(\dfrac{100 + 10}{100}\bigg)^{2}} \\ \\ \\ \implies \sf{A = 3630\bigg(\dfrac{110}{100}\bigg)^{2}} \\ \\ \\ \implies \sf{A = 3630 \times \dfrac{110}{100} \times \dfrac{110}{100}} \\ \\ \\ \implies \sf{A = 363 \times \dfrac{110}{100} \times \dfrac{110}{10}} \\ \\ \\ \implies \sf{A = 363 \times \dfrac{11}{10} \times 11} \\ \\ \\ \implies \sf{A = 4392.3} \\ \\ \\ \therefore \purple{\sf{A = 4392.3}}$,

Hence , the amount is ₹ 4392.3 .

Answer 2

Answer:

₹3000 is the answer of the solution