what sum of money will yield a simple interest of rupees 1155 in 3years 6months at 11 percent p.a.?
Answers
Answered by
32
S.I = ( P*R*T )/100
so, 1155 = p*3.5*11/100 [as 3yrs,6months=3.5 yrs]
1155*100 = 38.5p
115500/38.5=p
3000=p
therefore, the principal/sum of money is rs.3000
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Answered by
4
Answer:
S.I=Rs.1155
Rate(R)=11%p.a.
Time(T)=3years6months
=3
2
1
=
2
7
years
∴Principal=
R×T
S.I.×100
=
11×7
1155×100×2
=Rs.3000
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