Question

What sum of money will yield an interest of 3600 in 6 years at the rate of 8% p.a.?
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Answer 1

Step-by-step explanation:

FORMULA FOR INTEREST :- PTR/100

P = 3,600

T = 6years

R = 8%

APPLYING FORMULA :-

ㅤ☞︎︎︎PTR/100

ㅤ☞︎︎︎3,600x6x8/100

ㅤ☞︎︎︎36x6x8

ㅤ☞︎︎︎1,728

Sum of money is :- P+I

ㅤㅤㅤㅤㅤㅤㅤ☞︎︎︎3,600+1,728

ㅤㅤㅤㅤㅤㅤㅤ ☞︎︎︎ 5,328rs

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Answer 2

Answer :-

• The sum of money will yield an interest of Rs. 3600 in 6 years at the rate of 8% p.a. is Rs. 7500

Step-by-step explanation ::

To Find :-

• The sum of money [ principal ]

Solution :-

Given that,

• Principal = Rs. 3600
• Time = 6 years
• Rate = 8%

Therefore, the sum of money is,

As we know that,

$\underline{\boxed{\bf{Principal = \dfrac{S.I. \times 100}{R \times T}}}}$

Where,

• S.I. = Simple interest
• R = Rate
• T = Time

According the question,

$\sf{ \longmapsto \: Principal = \dfrac{3600 \times 100}{8 \times 6}} \\ \\ \\ \sf{ \longmapsto \: Principal = \dfrac{360000}{8 \times 6}} \\ \\ \\ \sf{ \longmapsto \: Principal = \dfrac{360000}{48}} \\ \\ \\ \sf{ \longmapsto \: Principal = \cancel{\dfrac{360000}{48}}} \\ \\ \\ \bf{ \longmapsto \: Principal = 7500}$

• The sum of money is Rs. 7500.

More information

Some important formulas related to Simple interest :-

$\bull \: \: \sf{Principal = \dfrac{S.I. \times 100}{R \times T}}$

$\bull \: \: \sf{Rate = \dfrac{S.I. \times 100}{P \times T}}$

$\bull \: \: \sf{Time = \dfrac{S.I. \times 100}{R \times P}}$

$\bull \: \: \sf{Simple \: Interest = \dfrac{P \times R \times T}{100}}$