Question

What sum will amount to 5216.40 in two years at compound interest, if the rates of interest are 8% and 5% p.a. for two successive years?​

Answer 1

Answer:

It is given that

It is given that Amount (A)=2782.50

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100)

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100) n

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100) n

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100) n Substituting the values

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100) n Substituting the values 2782.50=P(1+5/100)(1+6/100)

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100) n Substituting the values 2782.50=P(1+5/100)(1+6/100)By further calculation

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100) n Substituting the values 2782.50=P(1+5/100)(1+6/100)By further calculation 2782.50=P×21/20×53/50

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100) n Substituting the values 2782.50=P(1+5/100)(1+6/100)By further calculation 2782.50=P×21/20×53/50So we get

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100) n Substituting the values 2782.50=P(1+5/100)(1+6/100)By further calculation 2782.50=P×21/20×53/50So we get P=2782.50×20/21×50/53

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100) n Substituting the values 2782.50=P(1+5/100)(1+6/100)By further calculation 2782.50=P×21/20×53/50So we get P=2782.50×20/21×50/53Multiply and divide by 100

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100) n Substituting the values 2782.50=P(1+5/100)(1+6/100)By further calculation 2782.50=P×21/20×53/50So we get P=2782.50×20/21×50/53Multiply and divide by 100P=278250/100×20/21×50/53

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100) n Substituting the values 2782.50=P(1+5/100)(1+6/100)By further calculation 2782.50=P×21/20×53/50So we get P=2782.50×20/21×50/53Multiply and divide by 100P=278250/100×20/21×50/53P=2500

It is given that Amount (A)=2782.50Rate of interest for two successive years =5% and 6%We know that A = P(1+r/100) n Substituting the values 2782.50=P(1+5/100)(1+6/100)By further calculation 2782.50=P×21/20×53/50So we get P=2782.50×20/21×50/53Multiply and divide by 100P=278250/100×20/21×50/53P=2500Hence, the principal is 2500

Answer 2

Step-by-step explanation:

$\large\green{\sf{⚡Apporpiate Question ⚡}}$

What sum will amount to 5216.40 in two years at compound interest, if the rates of interest are 8% and 5% p.a. for two successive years?

$\large\green{\sf{⚡Answer⚡}}$

It is given that 

Amount (A)=2782.50

Rate of interest for two successive years =5% and 6%

We know that 

A = P(1+r/100)n

Substituting the values 

2782.50=P(1+5/100)(1+6/100)

By further calculation 

2782.50=P×21/20×53/50

So we get 

P=2782.50×20/21×50/53

Multiply and divide by 100

P=278250/100×20/21×50/53

P=2500

Hence, the principal is 2500