Question

What sum will amount to * 6,600 in
4 years at 8% per annum simple interest ?
(A) 6,000 (B) 35,000
(C) 4,000 (D) 36,200

​

Answer 1

SI
= 6600
r = 8
n = 4
SI = PNR/100
6600=p*4*8/100
6600*100/8*4
20625

Answer 2

$\red{ \huge{ \underline{ \overline{ \mid{ \bold{ \purple{ \: \: SOLUTION \: \: \red{ \mid}}}}}}}}$

$\underline{\underline{ \bold{ \: \: GIVEN\: \: : }}} \to \\ \\ \bold{Amount \: \: ,A = Rs. \: 6600} \\ \\ \bold{Rate \: \: of \: \: interest \:, \: R = 8\%} \\ \\ \bold{Time \: \: T= 4 \: \: years}$

$\bold{ Let , }\\ \\ \bold{Principal \:, \: P = Rs. \: X }$

$\underline{ \bold { \: \: We \: \:know \: \: that \: \: }} \\ \\ \bold{S.I = Amount \: - \: Principal} \\ \\ \bold{\Longrightarrow \:\frac{P \times R \times T}{100} \: = \: 6600 \: - \: X } \\ \\ \bold{\Longrightarrow \: \frac{ X \: \times 8 \times 4}{100}\: = \: 6600 \: - \: X}\\ \\ \bold{\Longrightarrow \: \frac{32X}{100}\: = \: 6600 \: - \: X} \\ \\ \bold{\Longrightarrow \:\frac{32X}{100} + X\: = \: 6600} \\ \\ \bold{\Longrightarrow \: \frac{132X}{100}\: = \:6600} \\ \\ \bold{\Longrightarrow \: 132X \: = \:660000} \\ \\ \bold{\Longrightarrow \: X = \frac{660000}{132}}\\ \\ \bold{\Longrightarrow \: X \: = \: 5000}$

$\bold{ \therefore \: Principal \: , \: P \: = \: Rs. \: 5000}$

$\bold{Hence ,}$

$\bold{\red{Rs. \: 5000}\: \: \: will \: \: amounted \: \: to \: \: Rs. \: 6600}$

$\bold{at \: \: the \: \: rate \: \: of \: \: 8\% \: \: per \: \: annum \: \: in}$

$\bold{4 \: \: years \: \: at \: \: simple \: \: interest \: .}$