Question

What sum will amount to ₹676 at 4 percent p.a. in 2 years if interest idls compounded yearly​

Answer 1

Answer:

Given, amount will becomes 676 after 2 years. e.g., A = 676 Rs. rate of interest , r = 4 % per annum. P = 625 Rs.

Answer 2

Answer:

Appropriate Question :-

• What sum will amount to ₹676 at 4% p.a. in 2 years if interest is compounded yearly.

Given :-

• A amount of ₹676 at 4% p.a. in 2 years if interest is compounded yearly.

Solution :-

Let,

$\mapsto \bf Sum =\: P$

Given :

• Amount = ₹676
• Rate of Interest = 4% p.a.
• Time Period = 2 years

According to the question by using the formula we get,

$\implies \sf\boxed{\bold{A =\: P\bigg(1 + \dfrac{r}{100}\bigg)^n}}$

where,

• A = Amount
• P = Principal
• r = Rate of Interest
• n = Time Period

So, by putting those values we get,

$\implies \sf 676 =\: P\bigg(1 + \dfrac{4}{100}\bigg)^2$

$\implies \sf 676 =\: P\bigg(\dfrac{100 \times 1 + 4}{100}\bigg)^2$

$\implies \sf 676 =\: P\bigg(\dfrac{100 + 4}{100}\bigg)^2$

$\implies \sf 676 =\: P\bigg(\dfrac{104}{100}\bigg)^2$

$\implies \sf 676 =\: P\bigg(\dfrac{104}{100} \times \dfrac{104}{100}\bigg)$

$\implies \sf 676 =\: P\bigg(\dfrac{104 \times 104}{100 \times 100}\bigg)$

$\implies \sf 676 =\: P\bigg(\dfrac{10816}{10000}\bigg)$

$\implies \sf 676 =\: P \times \dfrac{10816}{10000}$

$\implies \sf 676 =\: \dfrac{10816P}{10000}$

By doing cross multiplication we get,

$\implies \sf 10816P =\: 676 \times 10000$

$\implies \sf 10816P =\: 6760000$

$\implies \sf P =\: \dfrac{6760000}{10816}$

$\implies \sf\bold{\underline{P =\: ₹625}}$

$\therefore$ The sum or the principal is ₹625 .