What sum will become rupees 5,000 after 2 years at 10% p.a. compound interest use this formula A=P(1+R upon 100)
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A= P(1+r/100)^n
A= P(1+10/100)^2
A=P(11/10)^2
A= P×(121/100)
P= (A×100)/121
P=(5000×100)/121
P= 4132.23
I hope this answers your question sufficiently. Happy learning.
A= P(1+10/100)^2
A=P(11/10)^2
A= P×(121/100)
P= (A×100)/121
P=(5000×100)/121
P= 4132.23
I hope this answers your question sufficiently. Happy learning.
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