What temperature (in °C) did an ideal gas shift to if it was initially at -20.0 °C at 4.33 bar and 35.0 L and the pressure was changed to 8.71 bar and the volume changed to 15.0 L?
_____°C
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Answer:
T2 will be - 55°C
Explanation:
According to ques
PV/T = constant
P1= 4.33 bar
P2=8.71 bar
V1= 35L
V2= 15L
T1= - 20°C= 253K
SO, 4.33×35/253=8.71×15/ T2
T2= 218k
T2= 218k = - 55°C
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