Question

What temperature would be necessary to double the volume of a gas initialy at s.t.p if pressure is
decreased by 50%?​

Answer 1

Answer:

Y gas law. V1*p1/T1=V2*p2/T2 given.-v1=v P1=760mm of hg T1=273K v2=2v P2=360mm of Hg Therefore.720*v/273=360*2v/t2 T2=273k=0c