What temperature would be necessary to double the volume of a gas initially at s.t.p. if the pressure is decreased by 50 percent
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Answered by
67
y gas law. V1*p1/T1=V2*p2/T2 given.-v1=v P1=760mm of hg T1=273K v2=2v P2=360mm of Hg Therefore.720*v/273=360*2v/t2 T2=273k=0c
Whatareudoing:
how do you get p2 as 360
Answered by
42
use the formula p1v1/t1 = p2v2/t2
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