Question

what the action of zinc and hydrochloric acid on ethyl chloride​

Answer 1

Answer:

"Generally, when an "alkyl halide" is treated with "zinc" and "hydrochloric acid", it is "reduced" to the "respective alkane". The "nascent hydrogen" formed by the "reaction" between "zinc" and "HCl acid" reduces "ethyl chloride to ethane". ... When 2-bromopropane is reduced in presence palladium to form propane."

Answer 2

Answer:

The "nascent hydrogen" formed by the "reaction" between "zinc" and "HCl acid" reduces "ethyl chloride to ethane".