what the no. must be added to get each of tge no. 5,12,11,21 to get the no. in ptoportion
Answers
Step-by-step explanation:
Your answer
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Let the required number added be x
(5 + x) : (11 + x) : : (12 + x) : (21 + x)(5+x):(11+x)::(12+x):(21+x)
\begin{gathered} = > \frac{5 + x}{11 + x} = \frac{12 + x}{21 + x} \\ \\ = > (5 + x)(21 + x) = (11 + x)(12 + x) \\ \\ = > 5(21 + x) + x(21 + x) = 11(12 + x) + x(12 + x)\end{gathered}
=>
11+x
5+x
=
21+x
12+x
=>(5+x)(21+x)=(11+x)(12+x)
=>5(21+x)+x(21+x)=11(12+x)+x(12+x)
= > 105 + 5x + 21x + x {}^{2} = 132 +11x + 12x + x {}^{2}=>105+5x+21x+x
2
=132+11x+12x+x
2
= > 105 + 26x + x {}^{2} = 132 + 23x + x {}^{2}=>105+26x+x
2
=132+23x+x
2
= > 26x - 23 x + x {}^{2} - x {}^{2} = 132 - 105=>26x−23x+x
2
−x
2
=132−105
\begin{gathered} = > 3x = 27 \\ \\ = > x = \frac{27}{3} \\ \\ = > x = 9\end{gathered}
=>3x=27
=>x=
3
27
=>x=9
Hence, the required number is 9
Hope it help you