Question

what the numerical value of the vector 4i cap + 2jcap +k cap​

Answer 1

Answer:

$|i + j + k | = \sqrt{ {i }^{2} + {j }^{2} + {k }^{2} }$

now, i = 4

j = 2

k = 1

so,

$\sqrt{ {4}^{2} + {2}^{2} + {1}^{2} } \\ = \sqrt{16 + 4 + 1} \\ = \sqrt{21} = answer$