What the remainder for x^2018+2018 divided by x-1?
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Question: x^2018+2018 ÷ x-1
Answer:
x^2018+2018 [Equation 1 ]
Take,
x-1
x-1=0
x=1
Substitute x=1 in [Equation 1 ]
We get,
= x^2018+2018
= ( 1 )^2018+ 2018
Since anything power 1 is 1
= 1+2018
= 2019
It's the required result.
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