Math, asked by Rajpermansoor, 10 months ago

what three brothers divide a prize as follows. the oldest received 2/5 of it, middle received 1/3 of it. and youngest received the remaining 120 rupes. what was the value of prize​

Answers

Answered by jainsaurabh3
8

Answer:

Step-by-step explanation:

Let total money received by brothers be x

Money received by oldest =2/5x

Money received by middle=1/3x

Money received by younger=₹120

So according to the question

2x/5+1x/3+120=X

By solving it

6x+5x/15+120=X

11x/15+120=X

120=x - 11x/15

4x/15=120

So X =450

Putting in equations

Oldest brother got=2/5×450=180

Middle one got=1/3×450=150

And total value =180+150+120=430

Hope it will help you

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