what three brothers divide a prize as follows. the oldest received 2/5 of it, middle received 1/3 of it. and youngest received the remaining 120 rupes. what was the value of prize
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Answer:
Step-by-step explanation:
Let total money received by brothers be x
Money received by oldest =2/5x
Money received by middle=1/3x
Money received by younger=₹120
So according to the question
2x/5+1x/3+120=X
By solving it
6x+5x/15+120=X
11x/15+120=X
120=x - 11x/15
4x/15=120
So X =450
Putting in equations
Oldest brother got=2/5×450=180
Middle one got=1/3×450=150
And total value =180+150+120=430
Hope it will help you
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