Question

What total volume in litre at six hundred degree celsius and 1 atm could be formed by the decomposition of 16 gram of nh4no3?

Answer 1

Answer:

Hi mate!!!!

16 gram of nh4no3 has n.o of moles =given mass /molar mass

=16/80=0.2

According to ideal gas equation :

PV=nRT

1*V=0.2*0.083*

(600+273)

V=144.9(approx)