Question

What transition in the hydrogen spectrum would have the same wavelength as the balmer transition n = 4 to n = 2 of he+ spectrum ?

Answer 1

Q)

What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition n=4 to n=2 of He+He+ spectrum ?

(a)2,3(b)3,1(c)3,2(d)1,2

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Answers

For He+,1λHe+,1λ=RHz2[122−142]=RHz2[122−142]

For H,1λH,1λ=RH[1n21−1n22]=RH[1n12−1n22]

Since λλ is same

∴Z2[122−142]=[1n21−1n22]∴Z2[122−142]=[1n12−1n22]

z=2z=2

[112−122]=[1n21−1n22][112−122]=[1n12−1n22]

n1=1n1=1 and n2=2n2=2

Hence (d) is the correct answer.

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