Question

What transition in the hydrogen spectrum would have the same wavelength?

Answer 1

Answer:

For an atom = 1/λ = RHZ2 (1/n12-1/n22)

For He+ spectrum Z = 2,  n2=4,  n1= 2

Therefore = 1/λ = RH x 4(1/22-1/42) = 3RH/4

For hydrogen spectrum = 3RH/4,  Z = 1

Therefore = 1/λ = RH X 1(1/n12-1/n22)

Or

RH (1/n12-1/n22) = 3RH/4

Or

1/n12-1/n22  = 3/4

Which can be so for n1=1 & n2 = 2, i.e the transition is from n = 2 to n=1

Answer 2

Answer:

❤️❤️The wave number for Balmer transition of n =4 to n=2 of He⁺ spectrum would be:-

Acc. to question, the transition for Hydrogen will have the same wavelength:-

This equation can only be true when and

The transition of electron from n = 2 to n = 1 in Hydrogen would have the same wavelength as transition of electron from n = 4 to n = 1 in ❤️❤️

Explanation:

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