What type of bond will be formed if
a)A(atomic number 11) combines with B(atomic number 9)
b) C (aomic number 15) combines with D(atomic number 17)
Explain with the help of Lewis dot structure.
Answers
A] = COVALENT BOND
B] = COVALENT BOND
LEWIS STRUCTURE UNAVAILABLE
For qus
a) the kind of bond formed is ionic. Atomic number 11 for Sodium and 9 for Fluorine their compound is NaF
b) The kind of bond formed will be covalent . Fifteen for Phosphorus and 17 for Chlorine and their compound is PCl5
Explanation:
a) atomic number 11 lie.in first group of periodic table and 9 in 17th group of halogen. The difference between their atomic size , electronegativity is high.
Group 1 elements are electropositive metals {except hydrogen which is not metal but yes it is electropositive too}. They are ready to donate their valance electron. Electronegetivity of sodiyam is 0.93
Atomic number 9 lie in 17th group the group of most electronegative elements and fluorine is the most electronegative element with electronegativity 4.0
Difference between sodium and flourine electronegitivity is 2.07. All the bond having electronegitivity difference greater than 1.4 is ionic bond.
b) Group 15 and 17 both contains non metals and non metals always formed covalent bonds with each other.
Also if you wrote electronegitivity of Phosphorus and Chlorine which are 2.19 ans 3.16 respectively and their difference is 0.97 which is less than 1.4 so the bond is covalent