Question

What type of conditions we can apply on a−−√n. Write all details one by one.
$\frac{x}{x - 2} + 3 = \frac{2}{x - 2}$
solve the following equation
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Answer 1

Answer:

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Answer 2

Given :  $\dfrac{x}{x-2} +3=\dfrac{2}{x-2}$

To Find :  Solve the Equation  for x

Solution:

$\dfrac{x}{x-2} +3=\dfrac{2}{x-2}$

x -2 is in denominator hence  x - 2 ≠ 0

=>  x ≠ 2

Multiplying both sides by x - 2

=> x  + 3(x - 2)  = 2

=> x + 3x - 6  = 2

=> 4x  = 8

=> x = 2

But x ≠ 2

Hence no possible solution

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