What type of isomerism is exhibited by [co(nh3)4cl2]+br-?
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Answer: Both geometrical and optical isomerism.
Explanation:
Imagine a square sheet and then a line passing perpendicularly through the centre of that sheet. Now, place different ligands at each corner of square sheet and also at the end points of the line. This is an octahedral complex. Thus, geometrical isomerism with cis and trnas. Now, trans form having plane of symmetry (plane in which sheet lies if we place the ligands at the ends of the perpendicular axial line) is non-optical whereas in cis form, due to absence of any plane of symmetry, it is optically active.
Therefore, 2 geometrical and 2 optical isomers ( d and l form) are possible.
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