Math, asked by samyosuva7, 1 month ago

What type of quadrilateral is this? ABCD is a rhombus. APAD is equilateral ZABC = 100°, then find the measure of ZPCD D salo 24 y 056 P to 100 B A А 80 бо 80 Rectilinear Figures​

Answers

Answered by DevayaniPS
0

Answer:

Step-by-step explanation:

Join BD in ΔBCD,   BC and DC are given.  

So, we can calculate BD by applying Pythagoras theorem

⇒BD=  

BC  

2

+CD  

2

 

 

     =  

12  

2

+5  

2

 

 =  

144+25

=13 m=BD

⇒Area of □ABCD= Area of ΔABD+ Area of ΔBCD

⇒Area of ΔBCD

=  

2

1

×b×h=  

2

1

×12×5

=30  m  

2

 

⇒Area of ΔABD

=  

s(s−a)(s−b)(s−c)

 (Heron's formula)

⇒2S=9+8+13, S=  

2

30

 

⇒S=15  m

⇒Area of ΔABD

=  

15(15−9)(15−8)(15−13)

 

=  

15×6×7×2

=  

630×2

 

=6  

1260

=35.49m  

2

 

⇒Area of Park = Quad ABCD

=30+35.49

=65.49  m  

2

≈65.5  m  

2

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