What type of roots does the following quad function have? 3x^2-4x+1=0
Answers
Answered by
0
Answer:
two different real roots
Step-by-step explanation:
D = b²-4ac
D = 16 - 4(3)(1) = 4
here D > 0
hence this quadratic equation will have two real and distinct roots .
Answered by
0
Answer:
Real and distinct roots
Step-by-step explanation:
Given eq is 3x²-4x+1
Discriminant is b²-4ac = (-4)²-4(3)(1)
=16-12=4 (>0)
It is greater than zero
Therefore Eq has two real and distinct roots
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