What type of solution does the pair of equations 5x - 4y + 8=0 and 10x - 8y +16=0 has?
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Answer:
5x−4y+8=0⇒a
1
=5,b
1
=−4,c
1
=8
7x+6y−9=0⇒a
2
=7,b
2
=6,c
2
=−9
∴
a
2
a
1
=
7
5
6
−4
=
3
−2
c
2
c
1
=
−9
8
=
a
2
a
1
=
b
2
b
1
Therefore we have a unique solution.
Our system is consistent.
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