Question

What type of superconductor displays perfect diamagnetism?

Answer 1

• As we know that the superconductor exhibit perfect diamagnetism These magnetic fields are expelled because under the influence of a magnetic field, surface currents that flow without resistance develop to create magnetization within the superconductor.
• And This results in the superconductor having a magnetic susceptibility$-1$, meaning it exhibits perfect diamagnetism.

Following is the difference between type I and type II superconductors can be found in their magnetic behavior. A type I superconductor keeps out the whole magnetic field until a critical applied field Hc is reached. A type II superconductor will only keep the whole magnetic field out until a first critical field Hc1 is reached.

Answer 2

Answer:

1. These are usually made of pure metal.

2. When it is cooled below its critical temperature it exhibits zero resistivity and displays perfect diamagnetism.

3. This means that the magnetic fields cannot penetrate it while it is in the superconducting state.

4. This results in the superconductor having a magnetic susceptibility of -1, meaning it exhibits perfect diamagnetism.