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Answers
Explanation:
Correct Question:-
A piece of brass of volume 30cm³ has a mass of 252g. Find the density of the brass in (i) g/cm³ (ii) kg /m³
Answer:-
\red{\bigstar}★ Density of brass in
g/cm³ \large\leadsto\boxed{\rm\pink{8.4 \: g/cm^3}}⇝
8.4g/cm
3
kg/m³ \large\leadsto\boxed{\rm\pink{8400 \: kg/m^3}}⇝
8400kg/m
3
• Given:-
Volume of piece of brass = 30cm³
Mass of piece of brass = 252g
• To Find:-
Density of brass in g/cm³ and kg/g³
• Solution:-
We know,
\pink{\bigstar}★ \large\underline{\boxed{\bf\green{Density = \dfrac{mass}{volume}}}}
Density=
volume
mass
( i )
• Substituting in the Formula:-
➪ \begin{gathered}\sf Density = \dfrac{252 \: g}{30 \: cm^3} \\ \end{gathered}
Density=
30cm
3
252g
✯ \begin{gathered}\underline{\underline{\bf\red{Density = 8.4 g/cm^3}}} \\ \end{gathered}
Density=8.4g/cm
3
( ii )
• Converting g into kg:-
➪ \begin{gathered}\sf 252 \: g = \dfrac{252}{1000} \: kg \\ \end{gathered}
252g=
1000
252
kg
➪ \begin{gathered}\bf 0.252 \: kg \\ \end{gathered}
0.252kg
• Converting cm³ into m³:-
➪ \begin{gathered}\sf 30 \: cm^3 = 30 \times 10^{-6} m^3 \\ \end{gathered}
30cm
3
=30×10
−6
m
3
➪ \begin{gathered}\bf 30 \times 10^{-6} m^3 \\ \end{gathered}
30×10
−6
m
3
• Substituting in the Formula:-
➪ \begin{gathered}\sf Density = \dfrac{0.252 \: kg}{30 \times 10^{-6} \: m^3} \\ \end{gathered}
Density=
30×10
−6
m
3
0.252kg
➪ \begin{gathered}\sf Density = \dfrac{252 \: kg}{30 \times 1000 \times 10^{-6} \: m^3} \\ \end{gathered}
Density=
30×1000×10
−6
m
3
252kg
➪ \begin{gathered}\sf Density = 8.4 \times 10^{-3} \: kg/m^3 \\ \end{gathered}
Density=8.4×10
−3
kg/m
3
✯ \underline{\underline{\bf\red{Density = 8400 \: kg/m^3}}}
Density=8400kg/m
3
Answer:
what u guys think will board exam will be conducted or not!!!
let me get to know what you guys think!!!
Explanation:
obviously.....