Question

What umber must be added to the numbers 30, 41, 63 and 85 so that the resultant numbers are in proportion

Answer 1

Heya friend!!
Rajdeep here...

Thanks for asking the question.
Let x be added to each number.

According to the sum,
[tex]\frac{30 + x}{41+x} = \frac{63+x}{85+x} \\ =\ \textgreater \ (30+x) (85+x) = (63 + x) (41 + x) \\ =\ \textgreater \ 2550 + 30x + 85x + x^{2} = 2583 + 63x + 41x + x^{2} \\ =\ \textgreater \ 2550 + 115x = 2583 + 104x \\ =\ \textgreater \ 115x - 104x = 2583 - 2550 \\=\ \textgreater \ 11x = 33 \\=\ \textgreater \ x = \frac{33}{11} \\=\ \textgreater \ x = 3[/tex]

Hence, 3 should be added.
Hope my answer is satisfactory!
Thanks...

Answer 2

Hello friend

⭐⭐ Here is your answer⭐⭐

Let the number be x So,that the resultant number are in proportion.

hence,

=) (30 + x) / (41 + x ) = (63 + x) / (85 +x)

=) By cross multiplication we get,

=) (30 + x ) (85+x) = (63 + x ) ( 41 + x)

=) 115x + 2550 = 104x + 2583

=) 115x - 104x = 2583 - 2550

=) 11x = 33

=) x = 33/11

=) x = 3


Therefore the number is 3 ...so that the resultant number are in proportion.

I hope this will helps you.

Thanks.