Math, asked by almas231, 11 months ago

What value of 38 square - 22 square upon 16 using suitable identity

Answers

Answered by gtststyle
48

Answer:


Step-by-step explanation:

38^2-22^2/16=(38+22)(38-22)/16

{Using the identity a^2-b^2=(a+b)(a-b)}

=>(38+22)(38-22)/16

=>(60)(16)/16

=>60


So,answer is 60.

Answered by sharonr
35

The value of 38 square - 22 square upon 16 using suitable identity is 60

Solution:

Given that,

We have to find value of :

\frac{38^2 - 22^2 }{16}

Use the following identity

a^2 - b^2 = (a+b)(a - b)

Therefore,

38^2 - 22^2 = (38 + 22)(38 - 22)\\\\38^2 - 22^2 = (60)(16)

Thus the given expression becomes,

\frac{38^2 - 22^2 }{16} = \frac{ 60 \times 16 }{16}\\\\Simplify\\\\\frac{38^2 - 22^2 }{16} =60

Thus the value of given expression is 60

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