what value of k, -4 is a zero of the polynomial p(x) = x2-2x-(2k+2) ? Also find the other zero
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Answer:
k=11
Step-by-step explanation:
Put x = -4
p(-4)=0=(-4)^2-2(-4)-{2(k)+2}
16+8-2-2k=0
16+6-2k=0
22-2k=0
-2k=0-22
-2k= -22
2k = 22
k=22/2
k=11
Hey, mate I have solved the question to the maximum extent I could.
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