what value of K is -3 ( a zero of polynomial) x square +11x +K
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11
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Answered by
5
p(x)= x^2+ 11x + k
p(-3) = (-3)^2 + 11(-3) + k
p(-3) => 9 - 33 + k = 0
=> -24 + k = 0
=> k= 24
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